instantaneous position of a partical at time t,is given by x=10+12t+8t square where x and t are in metre and second respectively find the

(a) initial velocity of a partical 

(b)velocity of a partical at t=3sec

(c)instantaneious accerlation of partical

(d)position of particalat t=5sec

Asked by puneetgarg2555 | 15th Jun, 2018, 07:20: PM

Expert Answer:

Position x(t) = 10 + 12 t + 8 t2 
 
velocity v(t) = dx/dt = 12 + 16 t
 
Initial velocity, v0 at t=0,  v0 = 12+16×0 = 12 m/s
 
velocity at t=3, v = 12+16×3 = 60 m/s
 
acceleration = dv/dt = 12 m/s2
 
position at t = 5, x(5) = 10 + 12×5 + 8×5×5 = 270 m

Answered by Thiyagarajan K | 18th Jun, 2018, 02:27: PM

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