In the given figure, two chords AC and BD of a circle intersect at E. if arc AB = arc CB, prove that BE = EC and AE = ED

Asked by pereiracalida | 14th Jan, 2018, 07:26: PM

Expert Answer:

 
begin mathsize 16px style In space triangles space ABE space and space DCE comma
angle BAE equals angle CDE space space space left parenthesis Angles space in space the space same space segment right parenthesis
angle ABE equals angle DCE space space space space left parenthesis Angles space in space the space same space segment right parenthesis
AB equals CD space space space space left parenthesis since space arc space AB equals arc space CD right parenthesis
rightwards double arrow triangle ABE approximately equal to triangle DCE space
rightwards double arrow BE equals EC space and space AE equals DE end style

Answered by Rashmi Khot | 16th Jan, 2018, 09:54: AM