In rhombus ABCD , prove that :
AB^2 + BC^2 + CD^2 + AD^2 = AD^2 + BD^2
Asked by simranmangnani2282.9sdatl | 13th May, 2020, 02:52: PM
Question: In rhombus ABCD , prove that AB2 + BC2 + CD2 + AD2 = AC2 + BD2
In rhombus ABCD, AC and BD are diagonals.
Let the point of intersect of both the diagonals be O.
As we know that the digonals of a rhombus bisect each other at right angles, we have
Answered by Renu Varma | 13th May, 2020, 03:33: PM
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