In how many ways can 5 girls and 3 boys be seated in a row so that no two boys are together?

Asked by Topperlearning User | 13th Sep, 2016, 02:58: AM

Expert Answer:

Let us first seat the 5 girls. This can be done in 5! Ways. For each such arrangement, the three boys can be seated only at the cross marked places.

There are 6 cross marked place and the three boys can be seated in  ways. Hence, by multiplication principle, the total numbers of ways=5!=14400

Answered by  | 13th Sep, 2016, 04:58: AM