in an experiment to find the focal length of a concave mirror , a graph is drawn between the magnitudes of u and v ... what is the graph like?? URGENT

Asked by Paraukkhal | 26th Feb, 2011, 01:31: AM

Expert Answer:

Dear student,
Let 1/image distance = x and 1/object distance = y. and 1/ focal length = k

We know 1/image distance + 1/object distance = [1/ focal length ]
x +y = k

y = - x + k and the graph is straight line and hence the slope of this straight line is -1.

Comparing it with the equation of y = mx + c m = -1 and c = k.
Hope this helps.

Answered by  | 26th Feb, 2011, 07:15: AM

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