in an experiment to find the focal length of a concave mirror , a graph is drawn between the magnitudes of u and v ... what is the graph like?? URGENT
Asked by Paraukkhal | 26th Feb, 2011, 01:31: AM
Expert Answer:
Dear student,
Let 1/image distance = x and 1/object distance = y. and 1/ focal length = k
We know 1/image distance + 1/object distance = [1/ focal length ]
Hence
x +y = k
y = - x + k and the graph is straight line and hence the slope of this straight line is -1.
Comparing it with the equation of y = mx + c m = -1 and c = k.
Hope this helps.
Team
Topperlearning.com
We know 1/image distance + 1/object distance = [1/ focal length ]
Hence
x +y = k
y = - x + k and the graph is straight line and hence the slope of this straight line is -1.
Comparing it with the equation of y = mx + c m = -1 and c = k.
Answered by | 26th Feb, 2011, 07:15: AM
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