In a sample of 100 pcs of item 'x' 10 are defective and in a sample of 90 pcs of item 'y' 6 are defective.check whether defective pcs of item 'x' is greater than item 'y' at a significance level of 0.10

Asked by RyanRobert | 2nd Feb, 2014, 08:28: PM

Expert Answer:

Probability of defective item from a sample of 100 pcs =x equals 10 over 100 equals 0.1
Probability of defective item from a sample of 90 pcs = Y equals 6 over 90 equals 1 over 15 equals 0.0667
Here,
0.1 greater than 0.0667 rightwards double arrow X greater than Y

Answered by  | 3rd Apr, 2014, 10:50: AM

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