CBSE Class 11-science Answered

Asked by Topperlearning User | 10 Nov, 2016, 03:14: AM

Expert Answer

$limit as x rightwards arrow 1 of open parentheses log subscript 5 space 5 x close parentheses to the power of log subscript x 5 end exponent equals limit as x rightwards arrow 1 of open parentheses log subscript 5 5 plus log subscript 5 x close parentheses to the power of log subscript x 5 end exponent equals limit as x rightwards arrow 1 of open parentheses 1 plus log subscript 5 x close parentheses to the power of log subscript x 5 end exponent equals limit as x rightwards arrow 1 of open parentheses 1 plus log subscript 5 x close parentheses to the power of fraction numerator 1 over denominator log subscript 5 x end fraction end exponent I f space x rightwards arrow 1 comma space t h e n space log subscript 5 x rightwards arrow 0 L e t space log subscript 5 x equals y equals limit as y rightwards arrow 0 of open parentheses 1 plus y close parentheses to the power of 1 over y end exponent equals e to the power of limit as y rightwards arrow 0 of 1 over y log left parenthesis 1 plus y right parenthesis end exponent to the power of limit as y rightwards arrow 0 of 1 over y log left parenthesis 1 plus y right parenthesis end exponent equals 1 space s o e to the power of limit as y rightwards arrow 0 of 1 over y log left parenthesis 1 plus y right parenthesis end exponent equals e$

Answered by | 10 Nov, 2016, 05:14: AM

CBSE Class 11-science Answered

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