CBSE Class 11-science Answered

$P r o v e space t h a t space limit as n rightwards arrow infinity of open parentheses 4 to the power of n plus 5 to the power of n close parentheses to the power of 1 over n end exponent equals 5$

Asked by Topperlearning User | 10 Nov, 2016, 03:09: AM

Expert Answer

$limit as n rightwards arrow infinity of open parentheses 4 to the power of n plus 5 to the power of n close parentheses to the power of 1 over n end exponent equals limit as n rightwards arrow infinity of open parentheses 5 to the power of n close parentheses to the power of 1 over n end exponent open parentheses 1 plus open parentheses 4 over 5 close parentheses to the power of n close parentheses to the power of 1 over n end exponent equals limit as n rightwards arrow infinity of open parentheses 5 to the power of n close parentheses to the power of 1 over n end exponent open parentheses 1 plus open parentheses 4 over 5 close parentheses to the power of n close parentheses to the power of open parentheses 5 over 4 close parentheses to the power of n.1 over n. open parentheses 4 over 5 close parentheses to the power of n end exponent L e t space open parentheses 4 over 5 close parentheses to the power of n equals z. space I f space n rightwards arrow infinity comma space t h e n space z rightwards arrow 0. equals 5. limit as z rightwards arrow 0 of open parentheses open parentheses 1 plus z close parentheses to the power of z close parentheses to the power of 0.0 end exponent equals 5. e to the power of 0.0 end exponent equals 5$

Answered by | 10 Nov, 2016, 05:09: AM

Please Login or Sign up to continue!

CBSE Class 11-science Answered

Choose Filters

Open In Ask A Doubt App ?

Get in Touch

Call / Whats App