if the zeroes of the polynomial p ( x) are a-b ,a and a+b ,find a and b

a-b, a+b and a are the roots of the polynomial

Sum of the roots of a cubic polynomial = -(coefficient of x² )/(coefficient of  x³)

a-b + a+b+ a = 3

3a = 3

a =1

Product of the roots of a cubic polynomial = (constant term )/(coefficient of  x³) 

(a-b)(a+b)a = 1

(1-b²) = 1

b = 0

Also, (a-b)a + (a+b)a + (a-b)(a+b) =- (coefficient of x )/(coefficient of  x³) 

(a-b)a + (a+b)a + (a-b)(a+b) = -1

1-b + 1+ b + 1 - b²  = -1

- b² = -4

b = +2, -2