CBSE Class 10 Answered
if sum of two numbers is 1215 and their HCF is 81, then the possible number of pairsof such numbers are
Asked by avanupama.srinath | 15 Sep, 2021, 05:07: PM
It is given that the sum of two numbers is 1215 and their H.C.F is 81
Since the H.C.F of two numbers is 81, the two numbers are 81x and 81y.
Now, 81x + 81y = 1215 [Sum of two numbers is 1215]
or, 81 (x + y) = 1215
or, (x + y) = 15
Such pairs of numbers whose sum is 15 are (1, 14), (2, 13), (4, 11), (7, 8)
For x = 1, y = 14; in this case the numbers are 1 × 81 = 81 and 14 × 81 = 1134
For x = 2, y = 13; in this case the numbers are 2 × 81 = 162 and 13 × 81 = 1053
For x = 4, y = 11; in this case the numbers are 4 × 81 = 324 and 11 × 81 = 891
For x = 7, y = 8; in this case the numbers are 7 × 81 = 567 and 8 × 81 = 648
Hence four pairs are possible.
Answered by Renu Varma | 15 Sep, 2021, 10:16: PM
Application Videos
Concept Videos
CBSE 10 - Maths
Asked by Sunita | 08 Aug, 2022, 01:06: PM
CBSE 10 - Maths
Asked by aayeshashaikh40.10 | 24 Jul, 2022, 06:42: PM
CBSE 10 - Maths
Asked by balajisenapati04 | 29 May, 2022, 10:02: PM
CBSE 10 - Maths
Asked by saxenaanuradha02 | 07 May, 2022, 09:41: PM
CBSE 10 - Maths
Asked by s10b1548.siona6347 | 24 Oct, 2021, 06:47: PM
CBSE 10 - Maths
Asked by radhabai871985 | 20 Oct, 2021, 08:45: PM
CBSE 10 - Maths
Asked by sanskar.sachan | 01 Oct, 2021, 10:11: AM
CBSE 10 - Maths
Asked by avanupama.srinath | 15 Sep, 2021, 05:07: PM
CBSE 10 - Maths
Asked by rakshitasingh973 | 30 Jun, 2021, 12:07: PM
CBSE 10 - Maths
Asked by pankhilgupta432 | 28 Jun, 2021, 05:41: PM