CBSE Class 12-science Answered
If angular acceleration= -mB theta/I
How is Omega that is angular velocity= √(mB/I)
Asked by prakriti12oct | 19 Feb, 2020, 12:22: AM
Expert Answer
If acceleration is constnant C times acceleration and C is negative ,
then the motion is SHM and magnitude of C is square of angular frequency.
x = A sin(ωt ) , ( dx/dt ) = Aω cos(ωt) ,
( d2x/dt2 ) = - Aω2 sin(ωt) = -ω2 [ A sin(ωt) ] = -ω2 x
Hence in the expression ,
we get
Answered by Thiyagarajan K | 19 Feb, 2020, 11:38: AM
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