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if an electron and proton having same momenta enter perpendicular to a magnetic field then
Asked by shamkishor8 | 01 Oct, 2021, 09:05: PM
Electron and proton are charged particle . When a charged particle enters in a magnetic field ,
so that its direction of motion is perpendicular to direction of magnetic field, then it ecounters a force  ( q B v ) ,
where q is magnitude of charge , B is magnetic field flux density and v is speed of charge.

This force is perpendicular to the direction of motion of charge. hence charge particle moves in a circular motion .

Magnetic force ( q B v ) acts as centripetal force for the circular motion of charged particle.

Hence we have , ( q B v ) = m ( v2 / R )

Above equation is used to get any unknown parameter of charged particle from other known values

For example if we know the charge q and speed v , we get mass m of charged particle from given
magnetic field flux density B and the observed radius R of circular motion.

From above expression , we get the radius of circular motion as ,  R = ( m v ) / (qB )

Since magnitude of charge for electron and proton are same, in a given magnetic field of flux density B,
radius of circular path of proton is greater than radius of electron.

Direction of circular motion determines sign of charge
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