If a ball launched with initial velocity of 25 m/s at 45 degree. Find the maximum range covered by the ball? 

Asked by sehgalgayrav810 | 29th May, 2020, 07:19: AM

Expert Answer:

R a n g e equals V subscript h o r i z o n t a l end subscript cross times t i m e R a n g e equals U C o s theta cross times fraction numerator 2 U S i n theta over denominator g end fraction R a n g e equals fraction numerator U squared S i n 2 theta over denominator g end fraction R a n g e equals fraction numerator open parentheses 25 close parentheses squared S i n open parentheses 2 cross times 45 to the power of 0 close parentheses over denominator g end fraction R a n g e equals 62.5 m

Answered by Utkarsh Lokhande | 29th May, 2020, 10:10: AM

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