If a b c are continued proportional fund 1/b^2 = 1/b^2-a^2 + 1/b^2 - c^2

Asked by bhajansah9955 | 22nd May, 2020, 09:27: AM

Expert Answer:

Given: a, b, c are in continued proportion
Therefore a/b = b/c = k (say)
i.e. b=ck, a=bk=ck2
To prove: 1/b2 = 1/(b2-a2) + 1/(b2-c2)
Error converting from MathML to accessible text.

Answered by Renu Varma | 22nd May, 2020, 09:57: AM