CBSE Class 11-science Answered
If a and b are two non zero unequal real numbers show that sec theta= 2rootab/a+b is impossible
Asked by rushabh1234 | 20 Nov, 2018, 11:24: AM
![begin mathsize 12px style s e c space theta space equals space fraction numerator 2 square root of a b end root over denominator a plus b end fraction space semicolon space space t h e n space w e space h a v e space cos space theta space equals space fraction numerator a plus b over denominator 2 square root of a b end root end fraction space............ left parenthesis 1 right parenthesis
sin space theta space equals space square root of 1 space minus space cos squared theta end root space equals space square root of 1 minus space fraction numerator open parentheses a plus b close parentheses squared over denominator 4 a b end fraction end root space equals space square root of negative fraction numerator left parenthesis a minus b right parenthesis squared over denominator 4 a b end fraction end root space.............. left parenthesis 2 right parenthesis end style](https://images.topperlearning.com/topper/tinymce/cache/b885424924f6f4ed7c5c45681745b7a5.png)
if eqn.(1) is true, we are not able to find sinθ from eqn.(2), because -ve number is coming inside square root.
Hence secθ can not be equal to ![begin mathsize 12px style fraction numerator 2 square root of a b end root over denominator open parentheses a plus b close parentheses end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/cfddafb9c66a248be6a6e35c32d296e9.png)
![begin mathsize 12px style fraction numerator 2 square root of a b end root over denominator open parentheses a plus b close parentheses end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/cfddafb9c66a248be6a6e35c32d296e9.png)
Answered by Thiyagarajan K | 23 Nov, 2018, 00:01: AM
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