Hypotenuse of a right triangle is 25cm and out of the remaining two sides, one is longer than the other by 5cm. Find the lengths of the other two sides
Asked by Hari Rajagopal Anayath
| 3rd Oct, 2013,
09:31: PM
Expert Answer:
Let one side is x cm
Then other side is (x+5) cm
x^2 + (x+5)^2 = (25)^2
x^2 + x^2 +10x + 25 = 625
2x^2 + 10x - 600 = 0
x^2 + 5x - 300 = 0
x^2 + 20x - 15x - 300 = 0
x(x+20) - 15(x+20) = 0
(x+20) (x-15) = 0
x = -20 x = 15
Side cannot be negative
So, therefore one side is 15cm
other side is (x+5) = (15+5) = 20cm
Let one side is x cm
Then other side is (x+5) cm
x^2 + (x+5)^2 = (25)^2
x^2 + x^2 +10x + 25 = 625
2x^2 + 10x - 600 = 0
x^2 + 5x - 300 = 0
x^2 + 20x - 15x - 300 = 0
x(x+20) - 15(x+20) = 0
(x+20) (x-15) = 0
x = -20 x = 15
Side cannot be negative
So, therefore one side is 15cm
other side is (x+5) = (15+5) = 20cm
Answered by
| 3rd Oct, 2013,
09:58: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change