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CBSE Class 12-science Answered

Hye .I want u to tell me the correct option .
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Asked by jain.pradeep | 29 Apr, 2019, 06:17: PM
answered-by-expert Expert Answer
Initial kinetic energy = (1/2)mv2 = (1/2)×1×22 = 2 J
 
initial x-direction momentum = mv = 1×2 = 2 kg m/s ; initial y-diection momentum = 0
 
case I :- Kinetic energy = 2×(1/2)×1×(√2)2 = 2 J ;
              x-direction momentum = 2×1×1 = 2 kg m/s  ; y-direction momentum = 1×1 - 1×1 = 0 ;
 
case II :-  Kinetic energy = (1/2)×1×22 = 2 J ;
                x-direction momentum = 2×1 = 2 kg m/s  ; y-direction momentum = 0 ;
 
case III :- Kinetic energy = 2×(1/2)×1×(√2)2 = 2 J ;
                 x-direction momentum = 1×1 = 1 kg m/s  ; y-direction momentum = 1×√2 = √2 kg m/s ;
 
Kinetic energy is conserved in all cases. Momentum is conserved only in cae-I and case-II
Answered by Thiyagarajan K | 30 Apr, 2019, 08:56: AM

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