how zncl2 help in prepration of haloalkanes in groove process?
Asked by gargimoitreyee | 17th Mar, 2018, 11:09: AM
Expert Answer:
Role of anhydrous ZnCl2:
It helps cleave the C–O bond. Being a Lewis acid, it coordinates with the oxygen
atom of the alcohols. This result in weakening of the C–O bond which ultimately
breaks to form carbocations.
Role of anhydrous ZnCl2:
It helps cleave the C–O bond. Being a Lewis acid, it coordinates with the oxygen
atom of the alcohols. This result in weakening of the C–O bond which ultimately
breaks to form carbocations.
Answered by Varsha | 17th Mar, 2018, 12:30: PM
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