how zncl2 help in prepration of haloalkanes in groove process?

Asked by gargimoitreyee | 17th Mar, 2018, 11:09: AM

Expert Answer:

Role of anhydrous ZnCl2:

It helps cleave the C–O bond. Being a Lewis acid, it coordinates with the oxygen

atom of the alcohols. This result in weakening of the C–O bond which ultimately

breaks to form carbocations.

Answered by Varsha | 17th Mar, 2018, 12:30: PM