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CBSE Class 10 Answered

how to solve this question?
Asked by | 05 Jun, 2008, 03:25: PM
Expert Answer

10ax2-6x+15ax-9=0

10ax2+15ax -6x -9=0

5ax(2x+3) -3(2x+3)=0

(5ax-3)(2x+3)=0

5ax-3 = 0 or 2x+3 = 0

x = 3/5a or x = -3/2

Answered by | 05 Jun, 2008, 05:25: PM
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