ICSE Class 9 Answered
How to solve
By substitution method.
Asked by eshaanbayale51.9spicertl | 31 May, 2020, 16:26: PM
![begin mathsize 16px style 5 straight x space plus space 6 straight y space equals space 7 space.... space left parenthesis 1 right parenthesis
3 straight x space plus space 2 straight y space equals space 5 space.... space left parenthesis 2 right parenthesis
From space left parenthesis 2 right parenthesis comma
straight y space equals space fraction numerator 5 minus 3 straight x over denominator 2 end fraction
Substituting space the space value space of space straight y space in space left parenthesis 1 right parenthesis comma space we space get
5 straight x space plus space 6 open parentheses fraction numerator 5 minus 3 straight x over denominator 2 end fraction close parentheses equals space 7
rightwards double arrow 5 straight x space plus space 3 open parentheses 5 minus 3 straight x close parentheses space equals space 7
rightwards double arrow 5 straight x space plus space 15 space minus space 9 straight x space equals space 7
rightwards double arrow space minus 4 straight x space equals space minus 8
rightwards double arrow space straight x space equals space 2
Therefore comma space straight y space equals space fraction numerator 5 minus 3 straight x over denominator 2 end fraction space equals space fraction numerator 5 minus 3 left parenthesis 2 right parenthesis over denominator 2 end fraction equals fraction numerator negative 1 over denominator 2 end fraction
rightwards double arrow straight x space equals space 2 space and space straight y space equals fraction numerator negative 1 over denominator 2 end fraction
end style](https://images.topperlearning.com/topper/tinymce/cache/f0c2293297830fa5b41619a9ad02155d.png)
Answered by Yasmeen Khan | 31 May, 2020, 21:33: PM
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