Request a call back

Hi tick the correct option in each case
The curve shows it is almost reaching the surrounding temperature 20 °C and change in temperature keep on decreasing and it is very less at   4  hour.  Hence, temperature will be very near to 20 °C

Energy loss  ΔE for change in temperature ΔT is given by  ΔE = m×Cp×ΔT ,
where m is mass of water and Cp is specific heat of water

if  ΔT = 1°C   ,  then Energy loss per °C,    m×Cp = 8×105 J /°C .................(1)

Rate of change of energy loss with repect to time,  (ΔE/Δt) = m×Cp×( ΔT/Δt) = 16×106 J/hour  ................(2)

from eqn.(1) and (2),  Rate of temperature falling,  ( ΔT/Δt) = 16×106 / ( 8×105)  = 20 °C/hour

Answered by Shiwani Sawant | 28 May, 2019, 02:26: PM

## Concept Videos

CBSE 12-science - Physics
Asked by mazhartahsildar143 | 07 May, 2020, 01:44: PM
CBSE 12-science - Physics
Asked by Hemanthrakshitha95 | 03 Mar, 2020, 02:55: PM
CBSE 12-science - Physics
Asked by shivakumarshreyas24 | 01 Mar, 2020, 08:12: AM
CBSE 12-science - Physics
Asked by khushimassey437 | 31 May, 2019, 08:41: AM
CBSE 12-science - Physics
CBSE 12-science - Physics
Asked by manasvijha | 19 Mar, 2019, 07:17: PM