CBSE Class 10 Answered
help plz pre boardz are on!
Asked by suchet_r | 09 Jan, 2010, 01:18: PM
Expert Answer
t2 - 15 = (t-15) (t+15)
So, the zeroes are 15 and -15.
coefficent of t2 = 1
coefficent of t = 0
constant = -15
Sum of zeroes = 15 + -15 = 0
-coefficent of t/ constant term = -0/1 = 0
So, Sum of zeroes = coefficent of t/ constant term
Product of zeroes = 15 x -15 = -15
constant/ coefficent of t = -15/1 = -15
So, Product of zeroes = constant/ coefficent of t
Answered by | 09 Jan, 2010, 02:11: PM
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