help plz pre boardz are on!

Asked by suchet_r | 9th Jan, 2010, 01:18: PM

Expert Answer:

t2 - 15 = (t-15) (t+15)

So, the zeroes are 15 and -15.

coefficent of t2 = 1

coefficent of t = 0

constant = -15

Sum of zeroes =  15 +  -15 = 0

-coefficent of t/ constant term = -0/1 = 0

So, Sum of zeroes = coefficent of t/ constant term

Product of zeroes =  15 x -15 = -15

constant/ coefficent of t = -15/1 = -15

So, Product of zeroes = constant/ coefficent of t

      

Answered by  | 9th Jan, 2010, 02:11: PM

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