CBSE Class 10 Answered
heights and distances
Asked by prgayathri | 26 Jan, 2009, 02:26: PM
Expert Answer
Imagine A to be the position of the man and AB=10 m(acc to qn)
Angle EAD= angle of elevation of the top of the hill=60 degrees
and
Angle DAC=Angle ACB=angle of depression =30 degrees
LeED=h, DC=x, AD=BC=y
According to question AB=10 so DC=10 as AB=DC( opposite sides of a rectangle)
Now,
in triangle EAD,
tan 60=h/y..(1)
in triangle ACB,
tan 30=10/y...(2)
So equating the value of y from both equations we get,
So distance of the hill from the ship==y= m
and height of the hill=h=30 m
Answered by | 27 Jan, 2009, 02:05: PM
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