heights and distances
Asked by suchet_r | 5th Oct, 2009, 08:32: PM
Let the height about the 60 m point be x and common side of the two triangles be y.
Then y = 60/tan 60 = 60/3 = 203
and tan 30 = x/y.
x = ytan30 = (203)(1/3) = 20 m
The height of the cloud above the lake surface is 60 + 20 = 80 m and above the point of observation is 20 m.
Answered by | 5th Oct, 2009, 10:00: PM
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