give me answer

S_n = n(2a₀+(n-1)d)/2

S_q = q(2a₀+(q-1)d)/2 = 2q+3q²     ..............(0)

2a₀+(q-1)d = 4+6q      .... (1)

Put q = q+1 in (0),

S_q+1 = (q+1)(2a₀+qd)/2 = 2(q+1)+3(q+1)²     ..............(0)

2a₀+qd = 4+6(q+1)    ... (2)

Subtracting (2) from (1),

d = 6.

The common difference is, 6.

Regards,

Team,

TopperLearning.