give me answer
Asked by | 15th Mar, 2010, 07:26: PM
Sn = n(2a0+(n-1)d)/2
Sq = q(2a0+(q-1)d)/2 = 2q+3q2 ..............(0)
2a0+(q-1)d = 4+6q .... (1)
Put q = q+1 in (0),
Sq+1 = (q+1)(2a0+qd)/2 = 2(q+1)+3(q+1)2 ..............(0)
2a0+qd = 4+6(q+1) ... (2)
Subtracting (2) from (1),
d = 6.
The common difference is, 6.
Regards,
Team,
TopperLearning.
Answered by | 15th Mar, 2010, 07:43: PM
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