Asked by | 30th Nov, 2009, 11:12: PM
We'll assume that the distance 2.7 cm is referred from the mid of the central bright fringe.
Since we are measuring from the centre of bright fringe.
It's 0.3 cm above and below the reference line. So 2.7 - 0.3 = 2.4 cm.
And next will be dark, and number of fringes 2.4/0.6 = 4.
Therefore dark, bright, dark, bright. And next is a dark.
So it's the third dark fringe.
Answered by | 1st Dec, 2009, 11:54: AM
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