CBSE Class 10 Answered
for what value
Asked by | 02 Jul, 2009, 06:20: PM
Expert Answer
comparing with the standard quadratic eqn we get,
a=p+1
b=-3(p-1)
c=-(p-1)
for the roots to be real and equal,
we must have the value of the discriminant equal to zero.
so
[9(p-1)(p-1)]+4[(p+1)(p-1)]=0
(p-1){ [9(p-1)]+4(p+1)]=0
(p-1)[13p-5]=0
so
p=1
or
p=5/13
p=13/5
Answered by | 02 Jul, 2009, 10:38: PM
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