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five years ago a man was seven time as old as his son. Five years hence, the man will be three times as old as his son. Find their present age
Asked by charan.cp24 | 05 Jan, 2023, 18:54: PM
Let the present ages of father and son be 'x' and 'y' years respectively.
According to the first condition, we have
(x-5) = 7(y-5)
i.e. x - 5 = 7y - 35
i.e. x - 7y = -30   ... (i)
According to the second condition, we have
(x+5) = 3(y+5)
i.e. x+5 = 3y + 15
i.e. x - 3y = 10   ... (ii)

Subtracting (i) from (ii), we get
4y = 40
Therefore, y = 10
So, x = -30 + 70 = 40
Thus, the age of father is 40 and age of son is 10.
Answered by Renu Varma | 06 Jan, 2023, 09:55: AM

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