Five point charges, each of the value +q coulombs are placed on the five vertices of a regular hexagon of side L metres. The magnitude of force on a charge -q coulomb placed at the centre of the hexagon is

Asked by Jogy Jacob | 31st Mar, 2013, 05:47: PM

Expert Answer:

If six same charges are placed at six vertices then the attractive forces will cancel each other.
So the net force on the centre charge will be 0.
So that is why the five point charges are taken.
Now solve the net frce by applying resolution of vectors concept.

Answered by  | 1st Apr, 2013, 03:50: PM

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