find the zeros
Asked by ashish854 | 2nd Feb, 2010, 07:09: PM
p(x) = x3 -6x2 + 11x - 6
On substituting x =1 in the polynomial.
p(1) = 1 - 6 + 11 - 6 = 0
So, (x-1) is a factor of the given polynomial p(x).
By long division, we get
So, x3 -6x2 + 11x - 6 = (x-1) (x2 -5x +6)
= (x-1) (x2 -2x -3x +6)
= (x-1)(x-2) (x-3)
So, the zeroes of the polynomial are 1,2 and 3.
Answered by | 3rd Feb, 2010, 09:07: AM
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