find the zeros

Asked by ashish854 | 2nd Feb, 2010, 07:09: PM

Expert Answer:

p(x) = x3 -6x2 + 11x - 6

On substituting x =1 in the polynomial.

p(1) = 1 - 6 + 11 - 6 = 0

So, (x-1) is a factor of the given polynomial p(x).

By long division, we get

So, x3 -6x2 + 11x - 6 = (x-1) (x2 -5x +6)

                                    = (x-1) (x2 -2x -3x +6)

                                    = (x-1)(x-2) (x-3)

So, the zeroes of the polynomial are 1,2 and 3.

 

Answered by  | 3rd Feb, 2010, 09:07: AM

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