Find the value of K
Asked by sunil_0010
| 22nd Jun, 2009,
03:38: PM
since -4 is a root of the given quad.eqn,
So,
x=-4 must satisfy that equation.
i.e. on putting x=-4, the LHS must be equal to the RHS.
so, we get,
16-4P-4=0
i.e.
p=3
So the other equation becomes,
(x*x)+4x+k=0
this equation has equal roots.So, the value of the discriminant for that eqn must be equal to zero.
So,
16-4k=0
which gives us that
k=4
Answered by
| 22nd Jun, 2009,
05:38: PM
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