Find the sum of natural numbers lying between 1 to 1000 which are divisible by 3.
Asked by ashleshathakur124 | 10th Feb, 2020, 09:46: PM
3, 6, 9, ..... 999 are the natural numbers between 1 to 1000 which are divisible by 3 and this is an A.P.
a = 3, d = 3 and an = 999
We know that,
an = a + (n - 1)d
→ 999 = 3 + (n - 1)3
→ 3(n-1) = 996
→ n = 333
Sn = n/2(a + l) = 333/2(3 + 999) = (333/2)×1002 = 166833
Answered by Yasmeen Khan | 11th Feb, 2020, 11:40: AM
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