CBSE Class 10 Answered
find the sum of all natural nos. between 100 and 999,which are multiples of 9.
Asked by riyaliz | 22 Jul, 2008, 09:58: PM
Expert Answer
The sum of natural numbers between100 and 999 , which are multiplesof 9 are 108 , 117 , ,,,,,........... 999
the number of terms = 108 + ( n - 1) x9 = 999
108 + 9n -9 = 999
99 + 9n = 999
n = 100
the sum of all numbers = 100 / 2 [ 2 x 108 + ( 99 x 9 ) ]
50 [ 216 + 891 ] = 55350
Answered by | 25 Jul, 2008, 08:23: PM
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