find the sum of all naturaL NO B/W 100 and 200 divisible by 4

Asked by  | 26th Feb, 2010, 09:33: AM

Expert Answer:

The first natural number which lies between 100 and 200 and is divisible by 4 is 104.

Similarly the series will be 104, 108, 112........................................196

nth observation = 196

Tn = a + (n-1)d

196 = 104 + (n-1) 4

196 = 104 + 4n - 4

196 = 100 + 4n

96 = 4n

Therefore, n = 24

Sum = (n/2) (a+l)

          = 12 (104 + 196)

         = 12 ( 300)

        = 3600

Hence the answer.

Answered by  | 26th Feb, 2010, 09:50: AM

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