CBSE Class 10 Answered
find the sum of all naturaL NO B/W 100 and 200 divisible by 4
Asked by | 26 Feb, 2010, 09:33: AM
Expert Answer
The first natural number which lies between 100 and 200 and is divisible by 4 is 104.
Similarly the series will be 104, 108, 112........................................196
nth observation = 196
Tn = a + (n-1)d
196 = 104 + (n-1) 4
196 = 104 + 4n - 4
196 = 100 + 4n
96 = 4n
Therefore, n = 24
Sum = (n/2) (a+l)
= 12 (104 + 196)
= 12 ( 300)
= 3600
Hence the answer.
Answered by | 26 Feb, 2010, 09:50: AM
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