Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

Find the equation of the parabola with vertex at the origin, passing through the point (-2,-3) and symmetric about the y axis.

Asked by Topperlearning User | 30 Apr, 2014, 11:31: AM
Expert Answer

Since the vertex is at the origin and the parabola is symmetric about the y axis it is of the form x2 = 4ay.The parabola passes through the point (-2,-3),hence the coordinates x=-2 and y=-3 must satisfy the equation of the parabola is x2 = 4ay

(-2)2 = 4a (-3)

4 = -12a a = -4/12 = -1/3.

Hence the equation of the porabola is x2 = -1/3y or 3x2 = -y

Answered by | 30 Apr, 2014, 01:31: PM
CBSE 11-science - Maths
Asked by dineshchem108 | 21 Oct, 2018, 07:54: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 27 Feb, 2015, 01:28: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 13 Nov, 2016, 05:55: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 30 Apr, 2014, 11:27: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 30 Apr, 2014, 11:28: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 30 Apr, 2014, 11:29: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 30 Apr, 2014, 11:29: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 13 Nov, 2016, 05:54: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 27 Feb, 2015, 01:20: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 30 Apr, 2014, 11:31: AM
ANSWERED BY EXPERT

Start your hassle free Education Franchisee and grow your business!

Know more
×