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Find the distance between the lines 4x-3y+5=0 and 8x-6y+7=0..
Asked by Suryavanshikatoch | 11 Feb, 2019, 07:37: PM

lines 4x-3y+5=0 and 8x-6y+7 =0 are parallel lines with slope 4/3 as shown in figure.

Point of intersection of both lines with y-axis is obtained by substituting x=0 in the equations.

Points of intersection A (0, 5/3) and B(0,7/6) are shown in figure.

Perpendiculr line to both the lines is in the form 3x+4y = k . This perpendicular line passes through A(0, 5/3)
by substituting values for x and y in the equation we get k = 20/3

point of intersection is obtained by solving the equations 8x-6y+7=0  and 3x+4y = (20/3)

we get point of intersection as C ( 0.24, 1.5)

distance between the lines =

Answered by Thiyagarajan K | 11 Feb, 2019, 10:24: PM

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