CBSE Class 12-science Answered
Find the area between x axis, x^2 + y^2 = 8x and y^2 = 4x
Asked by bjayanta | 20 Nov, 2018, 14:05: PM
x2 + y2 = 8x and y2 = 4x
x2 + 4x = 8x
x2 - 4x = 0
x(x - 4) = 0
x = 0 to x = 4
Required area = ![begin mathsize 16px style integral subscript 0 superscript 4 square root of 8 straight x minus straight x squared end root dx minus integral subscript 0 superscript 4 square root of 4 straight x end root dx end style](https://images.topperlearning.com/topper/tinymce/cache/fd77fbfc8a86943b1fac3c8c5069e17c.png)
![begin mathsize 16px style integral subscript 0 superscript 4 square root of 8 straight x minus straight x squared end root dx minus integral subscript 0 superscript 4 square root of 4 straight x end root dx end style](https://images.topperlearning.com/topper/tinymce/cache/fd77fbfc8a86943b1fac3c8c5069e17c.png)
Integrate it further.
Answered by Sneha shidid | 21 Nov, 2018, 09:35: AM
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