Find the A.P after inserting two arithmetic means between two numbers which are arithmetic means of the sequences 1,2,3,4 and 5,6,7,8 respectively?
Asked by Topperlearning User | 5th Oct, 2016, 06:08: AM
The first number is the arithmetic mean of 1,2,3,4 i.e.
The second number is the arithmetic mean of 5,6,7,8 i.e.
we need to insert two AMs between 5/2 and 13/2 after which the resulting sequence will be an AP with common difference given by
The first AM is 5/2+4/3=23/6
The second AM is 5/2+2(4/3)=31/6
The resulting AP is 5/2 , 23/6 , 31/6 , 13/2
Answered by | 5th Oct, 2016, 08:08: AM
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