# CBSE Class 11-science Answered

**Between 1 and 31, n numbers have been inserted in such a way that the resulting sequence is an A. P. and the ratio of 7th and (n – 1)**

^{th}numbers is 5 : 9. Find the value of n.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM

Expert Answer

Let A_{1}, A_{2}, A_{3}, …, A_{n} be n arithmetic means between 1 and 31 and common difference be d.

Total number of terms = n + 2

First term = 1, last term = (n + 2)

^{th}term = 31_{}

_{}

Thus, the number of inserted numbers is 14.

Answered by | 04 Jun, 2014, 03:23: PM

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