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CBSE Class 12-science Answered

Fig shows a plastic ball of mass m suspended by a light string in a uniform field of intensity e.the ball comes in equilibrium at an angle thita .if ex and ey are the x component and y component of the electric field, find the charge on the ball and the tension in the string  
Asked by sharmashiva3667.12sdatl | 07 Jun, 2020, 09:26: AM
answered-by-expert Expert Answer
I t apostrophe s space g i v e n space t h a t space t h e space p a r t i c l e space c o m e s space t o space e q u i l i b r i u m space a t space a n space a n g l e space theta space w. r. t space h o r i z o n t a l W h e n space e l e c t r i c space f i e l d space a c t s space a l o n g space a space d i r e c t i o n space w h i c h space m a k e s space a n space a n g l e space theta space w i t h space h o r i z o n t a l space t h e n space t h e space f o r c e s space a c t i n g space o n space t h e space b a l l space a r e space F subscript v e r t i c a l end subscript space equals space m g space minus space q E subscript y space F subscript h o r i z o n t a l space end subscript equals space q E subscript x space tan theta space equals space F subscript h o r i z o n t a l space end subscript over F subscript v e r t i c a l end subscript space equals space fraction numerator space q E subscript x over denominator m g space minus space q E subscript y end fraction rightwards double arrow space q E subscript x space equals space m g space tan theta space minus space q E subscript y tan theta therefore q space equals space fraction numerator m g tan theta over denominator E subscript x plus E subscript y tan theta space end fraction T e n s i o n space i n space t h e space s t r i n g space i s space g i v e n space a s comma space T space equals space square root of open parentheses F subscript h o r i z o n t a l space end subscript close parentheses squared plus open parentheses F subscript v e r t i c a l end subscript close parentheses squared end root space equals space square root of space open parentheses q E subscript x close parentheses squared plus open parentheses m g space minus space q E subscript y close parentheses squared space end root
Answered by Shiwani Sawant | 07 Jun, 2020, 04:18: PM

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