CBSE Class 10 Answered
Extremely difficult one
Asked by | 13 Feb, 2010, 07:19: PM
Expert Answer
Since the identity must hold for any angle A. Let's pick A = 30.
sin 30 = 1/2, cos 30 = 3/2, tan 30 = 1/3, and cot 30 = 3
(tanA+cotA)/(cosecA-secA) = (4/3)/(2-2/3) = 4/(23 - 2) = 2.732050808
Also (sinA + tanA)/2cotA = (1/2 + 1/3)/23 = (3+2)/12 = 0.311004234
LHS RHS.
Hence the equation must be incorrect, please recheck the equation, provide us additional details to help you better.
Regards,
Team,
TopperLearning.
Answered by | 14 Feb, 2010, 07:52: AM
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