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⭕ Explain this statement in detail, Thanks 😊
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Asked by jhajuhi19 | 10 Aug, 2021, 04:10: AM
answered-by-expert Expert Answer
Dear Student,
 
Enthalpy of reaction is calculated by-
increment straight H equals space straight E subscript straight f minus straight E subscript straight b Here space straight E subscript straight f space is space Activation space energy space of space forward space reaction straight E subscript straight b space is space activation space energy space of space backward space reaction. In space Endothermic space reactions comma space increment straight H greater than 0 straight E subscript straight f minus straight E subscript straight b space greater than 0 straight E subscript straight f greater than straight E subscript straight b
So, YOu can see that activation energy of forward reaction is more than activation energy of backward reaction in endothermic reaction.
Answered by Ravi | 11 Aug, 2021, 04:17: PM
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NEET neet - Chemistry
⭕ Explain this statement in detail, Thanks 😊
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Asked by jhajuhi19 | 10 Aug, 2021, 04:10: AM
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NEET neet - Chemistry
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Asked by sonal | 02 Dec, 2019, 11:13: AM
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NEET neet - Chemistry
The enthalpy of reaction is maximum in which of the following reaction?:-       (1)NaOH+ HCl➝NaCl+H2O,   (2)NaOH+HF➝NaF+H2O,  (3)NaOH+HBr➝NaBr+H2O, (4) All have same value. Please answer with detail explanation.
Asked by patra04011965 | 12 Nov, 2019, 09:21: AM
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NEET neet - Chemistry
Q no 106
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Asked by manasvijha | 08 Apr, 2019, 09:56: PM
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NEET neet - Chemistry
  CH3COOH(aq) → CH3COO- (aq) + H+ (aq), ΔrH° = 0.005 kcal g-1 Enthalpy change when 1 mole of Ca(OH)2, a strong base, is completely neutralised by CH3COOH (aq) in dilute solution is a) -27.4 kcal mol-1 b) -13.4 kcal mol-1 c) -26.8 kcal mol-1 d) -27.1 kcal mol-1 Correct answer is option 'C'. Can you explain this answer?
Asked by ntg432000 | 06 Mar, 2019, 11:26: AM
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