dual

Asked by chandant | 1st Oct, 2010, 05:00: PM

Expert Answer:

Dear Student
 
For any hydrogen like element:
 

where

 is the wavelength of the light emitted in vacuum;
 is the Rydberg constant for this element;
 is the atomic number, i.e. the number of protons in the atomic nucleus of this element;
 and  are integers such that .
For hydrogen, Z = 1
For Helium, Z = 2
 
Putting in the above expression:
 
λhelium = λhydrogen / 4 (for same transition) = 4860/4 = 1215 angstrom
 
We hope that satisfies your query.
 
Regards
Team 
Topperlearning

Answered by  | 1st Oct, 2010, 10:33: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.