JEE Class main Answered
Derive an expression for capacitance between two parallel lines having charge density and suspended by a distance
Asked by Leeshmadevandira | 11 Apr, 2019, 01:00: PM
Expert Answer
Let us consider the long parallel wires as line-charge dipole as shown in figure, +λ and -λ are charge/unit length .
Potential at location is given by,
potential at left wire surface , V+
potential at right wire surface , V-
potental difference between left and right wires , V+ - V- = V
Capacitance/unit Length
Answered by Thiyagarajan K | 12 Apr, 2019, 08:08: AM
Application Videos
JEE main - Physics
Asked by gamingbadboy085 | 01 May, 2024, 06:28: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by bhargavreddynellaballi | 30 Apr, 2024, 08:18: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ravichandraravula66 | 29 Apr, 2024, 11:20: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by kmani310507 | 28 Apr, 2024, 04:38: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by arivaryakashyap | 23 Apr, 2024, 10:40: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ratnadeep.dmr003 | 21 Apr, 2024, 11:06: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ksahu8511 | 19 Apr, 2024, 11:55: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by mohammedimroz | 13 Apr, 2024, 09:48: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by medhamahesh007 | 02 Apr, 2024, 11:11: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by gundlasumathi93 | 31 Mar, 2024, 02:13: PM
ANSWERED BY EXPERT