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CBSE Class 10 Answered

Dear experts, Kindly explain the question with a proper solution. Thank you.
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Asked by pratikshyadashrkl | 29 Mar, 2020, 10:08: PM
answered-by-expert Expert Answer
In the gas mixture , since N2 and He are in equal molar ratio, their partial pressures are alsoequal.
 
Partial pressure of N2 = 2000 mm of mercury ; Partial pressure of He = 2000 mm of mercury;
 
As per the given decrease of pressure of N2 with respect to time, 
 
N2 partial pressure will comedown to 500 mm of mercury in 1 hour.
 
By Graham's law of effusion, Rate of effusion is inversely prportional to square root of molar mass.
 
begin mathsize 14px style r subscript H e end subscript over r subscript N subscript 2 end subscript space equals space square root of M subscript N subscript 2 end subscript over M subscript H e end subscript end root space space equals space square root of 28 over 4 end root space equals space 2.646 end style
Being a lighter molecule, He will effuse 2.646 times faster than N2 .
 
Hence pressure of He decreases 2.646 times more compare to Nitrogen.
 
Hence partial pressure of He after 1 hour = 500 /2.646 = 189 mm of mercury
 
molar ratio of ( N2 /He )  = 500/189 = 2.646 /1
Answered by Thiyagarajan K | 30 Mar, 2020, 02:41: PM
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