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Dear experts, Kindly explain the question with a proper solution. Thank you.
In the gas mixture , since N2 and He are in equal molar ratio, their partial pressures are alsoequal.

Partial pressure of N2 = 2000 mm of mercury ; Partial pressure of He = 2000 mm of mercury;

As per the given decrease of pressure of N2 with respect to time,

N2 partial pressure will comedown to 500 mm of mercury in 1 hour.

By Graham's law of effusion, Rate of effusion is inversely prportional to square root of molar mass.

Being a lighter molecule, He will effuse 2.646 times faster than N2 .

Hence pressure of He decreases 2.646 times more compare to Nitrogen.

Hence partial pressure of He after 1 hour = 500 /2.646 = 189 mm of mercury

molar ratio of ( N2 /He )  = 500/189 = 2.646 /1
Answered by Thiyagarajan K | 30 Mar, 2020, 02:41: PM

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