coordinate geometry

Asked by  | 18th May, 2009, 04:34: PM

Expert Answer:

Q(0,1) is equidistant from P(5,-3) and R (x,6)

⇒ QP = QR

52 + (-3-1)2 = x2 + (6-1)2

On squaring

⇒ 25 + 16 = x2 + 25

⇒ x = +4, -4

Compute QR and PR by using the distance formula where coordinated of Q, P and R are known to us.

Answered by  | 19th May, 2009, 09:16: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.