CBSE Class 10 Answered
can the 14th question of ex 6.3 can it be proved like the following method
in triangle ADC and PMR
AC/PR=AD/ DM =1/2*BC/1/2*QR
AC/PR=AD/PM=DC/MR
therefore triangle adcsimilar pmr
angle C= angle R
then in triangle ABC and pqr
AB/PQ =AC/PR and ANGLE C= ANGLE R
SO TRIANGLE "ABC" SIMILAR
TRIANGLE "PQR" BY SAS
Asked by bharath sudhakar | 06 Aug, 2012, 09:26: PM
Expert Answer
No. The solution which you have written is incorrect.
The error is in the first step where you have written AC/PR=AD/ PM =1/2*BC/1/2*QR.
We are just given that AB/PQ = AC/PR = AD/ PM
There is no information given about the proportionality of sides BC and QR.
Answered by | 06 Aug, 2012, 09:59: PM
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