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CBSE Class 12-science Answered

Calculate the equilibrium constant for the following equilibruim reaction :- Fe(s) + CD2+ (aq) = Fe 2+ (aq) + Cd (s)
Asked by shruthianandjan11 | 11 Mar, 2018, 10:41: AM
answered-by-expert Expert Answer
We space have comma Fe subscript open parentheses straight s close parentheses end subscript space plus space Cd to the power of 2 plus end exponent subscript open parentheses aq close parentheses end subscript space space rightwards arrow space Fe to the power of 2 plus end exponent subscript open parentheses aq close parentheses end subscript space plus space Cd subscript open parentheses straight s close parentheses end subscript straight E to the power of 0 subscript bevelled Fe to the power of 2 plus end exponent over Fe end subscript space space equals space open parentheses negative 0.44 space straight V close parentheses straight E to the power of 0 space subscript bevelled Cd to the power of 2 plus end exponent over Cd end subscript space space equals space open parentheses negative 0.403 space straight V close parentheses straight E to the power of straight o subscript cell space equals space space straight E to the power of 0 subscript bevelled Fe to the power of 2 plus end exponent over Fe end subscript plus straight E to the power of 0 space subscript bevelled Cd to the power of 2 plus end exponent over Cd end subscript space space space space space space space space space space space space equals space 0.44 space minus space 0.40 space space space space space space space space space space space equals 0.4 space straight V straight E to the power of straight o subscript cell space space equals fraction numerator 0.0592 over denominator straight n end fraction log space straight K logK equals space fraction numerator nE to the power of straight o subscript cell over denominator 0.0592 end fraction space space space space space space space space space space equals fraction numerator 2 cross times 0.4 over denominator 0.0592 end fraction log space straight K equals space space 13.51 space space space space straight K equals space space 3.23 cross times 10 to the power of 13 space space space space space space space space space space space space
Answered by Varsha | 11 Mar, 2018, 04:45: PM

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CBSE 12-science - Chemistry
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