CBSE Class 11-science Answered
Calculate the dissociation constant of a monobasic acid having the degree of dissociation 2% in its 0.01M solution.
Asked by Topperlearning User | 28 Apr, 2015, 11:01: AM
Expert Answer
Use Ionization constant expression
Substitute the respective values; we get
Ka = (0.01)(0.02 x 0.02)/ (1 - 0.02)
= 4.08 x 10-6 M/L
Answered by | 28 Apr, 2015, 01:01: PM
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