Calculate concentration of nitric acid in moles per litre in a sample having density 1.41 g/ml and m

Asked by  | 9th Sep, 2008, 10:14: AM

Expert Answer:

69%nitric acid means the 69g HNO3 dissolved in 100 g of solution.

The molecular mass of HNO3 is 63 g mole-1

No of moles = 69/63 = 1.095

Volume of solution = 100/ 1.41= 70.92ml

concentration = 1.095/.07092L  =  15.44 moles per litre.

Answered by  | 25th Sep, 2008, 09:59: AM

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